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Mauricio Esguerra
EPCOS AG, Ferrites Division, Product Design Department
P. O. Box 801709, D-81617 Munich, GERMANY
Abstract – An extension to Hodgdon´s hysteresis equation and its solution for minor
loops in terms of measured major loops is presented. Various application relevant
parameters for soft ferrite materials are derived and the results compared to well-
known models for the small signal regime.
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Many attempts have been done in the
past to quantitatively describe
hysteresis loops. One of the most
promising approaches is the
description of the memory-effect
inherent to hysteresis by means of
differential equations [1,2]. The one
formulated by Hodgdon with the B-
field as dependent variable,
(
)
(
)
(
)
G+
G%
G%
GW
I % + J %= ⋅
− +
α
sgn
(1)
has two major advantages:
• direct integrability
• applicable to most practical
problems, where voltage (and
consequently flux density) rather
than current is the known signal
Hodgdon´s own solution starts from a
parametrization of the curve, whereas
the author’s approach is based on
regarding the major loop as the
particular solution of the equation [3].
From there all other solutions, e.g.
minor loops, can be obtained without
explicitly considering the material
functions I% and J%. The upper
+¶ % and lower +¶ % minor loop
branches can be therefore expressed
in terms of the corresponding
measured major loop branches + %
and + %.
The aim of the present work is to
improve two major aspects. On the
one hand calculated minor loops close
to saturation deviate systematically
from measured ones. On the other
hand the quality and/or number of
points of the measured major loops is
often not enough for an accurate minor
loop calculation.
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In order to remedy the first deficiency,
the differential equation has been
modified by regarding the parameter
α
as a function of % rather than of the
amplitude
ˆ
[3], the equation being still
integrable. From the solution for sym-
metric minor loops given in [3], eq. (3)
follows for the integral over
α
%:
)
ˆ
()
ˆ
(
ˆ
)
ˆ
(
ˆ
)
ˆ
(
ˆ
ˆ
)(
%+%+
%+%+
H
−
−
=
∫
−
′′
α
(2)
According to the symmetry of eq. (1)
the function
α
%is even, such that the
general integral is given by:
)(
ˆ
)(
)()(
ˆ
)()(
ˆ
)(
ˆ
)(
),(
11
11
22
22
)(
21
2
1
−
−
⋅
−
−
=
∫
≡
′′
α
(3)
The commutation curve needs also to
be modified with respect to [3], eq. (5)
in order to account for the above
mentioned improvement of the